Answer:
[tex]\theta = 30^{\circ}[/tex]
Step-by-step explanation:
Given:
Range: [tex]0^{\circ} \le \theta \le 90^{\circ}[/tex]
[tex]Sin \theta = \frac{1}{2}[/tex]
Required
Find [tex]\theta[/tex]
[tex]Sin \theta = \frac{1}{2}[/tex]
Take arcsin of both sides
[tex]sin^{-1}(sin\theta) = sin^{-1}(\frac{1}{2})[/tex]
[tex]\theta = sin^{-1}(\frac{1}{2})[/tex]
Using the sin table
[tex]\theta = 30^{\circ}[/tex]
