Answer:
The object travels 144,000,000 feet.
Step-by-step explanation:
The distance the object travel after t seconds is given by:
[tex]d(t) = 64t^2[/tex]
How far would the object travel after 1.5 * 10^3 seconds
This is d when [tex]t = 1.5 \times 10^3 = 1500[/tex], so [tex]d(1500)[/tex]
[tex]d(1500) = 64*1500^2 = 144000000[/tex]
The object travels 144,000,000 feet.
