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Ammonium chloride, ammonium sulfate and ammonium nitrate are used in fertilisers.
Ammonia reacts with nitric acid to make ammonium nitrate.
NH3 + HNO3 → NH4NO3
Calculate the mass of ammonia required to make 5.0 g of ammonium nitrate.
relative formula mass of NH3 = 17
relative formula mass of NH4NO3 = 80

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Answer:

1.0625 g

Explanation:

Number of moles in 5g of NH4NO3 = 5.0g/80g/mol = 0.0625 moles

Again the balanced reaction equation is;

NH3 + HNO3 → NH4NO3

So,

1 mole of NH3 yields 1 mole of NH4NO3

x moles of NH3 yields 0.0625 moles of NH4NO3

x = 0.0625 moles of NH3

Mass of NH3 = number of moles * molar mass

Mass of NH3 = 0.0625 moles * 17g/mol

Mass of NH3 = 1.0625 g

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