Answer:
[tex]V=1.76\times 10^{-4}\ V[/tex]
Explanation:
Given that,
The diameter of a wire, d = 1.628 mm
Radius, r = 0.814 mm = 0.000814m
Current, I = 12.5 mA
The length of the wire, l = 2m
The resistivity of the wire, [tex]\rho=1.47\times 10^{-8}\ \Omega-m[/tex]
We need to find the potential difference across the wire. We know that the resistance of the wire is given by :
[tex]R=\rho\dfrac{l}{A}[/tex]
Also, V = IR
[tex]\dfrac{V}{I}=\rho\dfrac{l}{A}\\\\V=\dfrac{\rho l I}{A}\\\\V=\dfrac{1.47\times 10^{-8}\times 2\times 12.5\times 10^{-3}}{\pi \times (0.000814)^2}\\\\V=1.76\times 10^{-4}\ V[/tex]
So, the potential difference of the wire is [tex]1.76\times 10^{-4}\ V[/tex].
