Respuesta :
Answer:
the change in momentum is 2.52 N·s
the constant force on the ball while in contact with the players foot is 126 N
Explanation:
p=momentum
m=mass
v=change in velocity
p=(0.42)(6)
p=2.52
The change in the ball's momentum is 2.52 kgms⁻¹
The constant force exerted by the players foot on the ball is 126 N
From the question,
We are to determine the change in momentum of the ball
Change in momentum calculated by using the formula,
[tex]\rho = m(v-u)[/tex]
Where [tex]\rho[/tex] is the change in momentum
[tex]m[/tex] is the mass
[tex]v[/tex] is the final velocity
and [tex]u[/tex] is the initial velocity
From the given information,
[tex]m = 0.42 \ kg[/tex]
[tex]u = 12 \ m/s[/tex]
[tex]v = 18 \ m/s[/tex]
Therefore,
Change in the ball's momentum,
[tex]\rho = 0.42 (18-12)[/tex]
[tex]\rho = 0.42 (6)[/tex]
[tex]\rho = 2.52 \ kgms^{-1}[/tex]
Hence, the change in the ball's momentum is 2.52 kgms⁻¹
For the force exerted by the players foot
Force is given by change in momentum with time
That is,
[tex]F = \frac{\rho}{t}[/tex]
Where
[tex]F[/tex] is the force
[tex]\rho[/tex] is the change in momentum
and [tex]t[/tex] is the time
From the given information
[tex]t = 0.020 \ s[/tex]
Therefore,
[tex]F = \frac{2.52}{0.020}[/tex]
[tex]F = 126 \ N[/tex]
Hence, the constant force exerted by the players foot on the ball is 126 N
Learn more on calculating change in momentum here: https://brainly.com/question/12144602
