The statement that could be false on the interval is if x is greater than π/2
Given the function g(x)=√ 1−sin2x
We are to get the value of x that will make the function not exist. For the function not to exist, hence:
sin2x> 1
Solve the expression for x
2x > arcsin(1)
2x > π
x > π/2
This shows that the statement that could be false on the interval is if x is greater than π/2
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