Respuesta :
Answer:
[tex]F=2.30\times 10^{-26}\ N[/tex]
Explanation:
The distance between two electrons, d = 0.10 m
We need to find the magnitude of the electrostatic force on an electron by another electron.
The electrostatic force between two charges is given by :
[tex]F=k\dfrac{q_1q_2}{d^2}[/tex]
Substitute all the values,
[tex]F=\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(0.1)^2}\\\\F=2.30\times 10^{-26}\ N[/tex]
So, the magnitude of the electrostatic force between two electrons is [tex]2.30\times 10^{-26}\ N[/tex].
It is a force imposed by one charge on another as a result of the field. The magnitude of the electrostatic force will be 2.30×10⁻²⁶N.
What is the electrostatic force?
It is a force imposed by one charge on another as a result of the field. The electrostatic force produced by one line charge on another line charge is inverse of the square of the radius.
The electrostatic force is determined by the charge potency of each charge as well as the separation distance between them.
The given data in the problem is;
q=q₁=q₂ is the electric charge = 1.6×10⁻¹⁹C
r is the distance between the two charge=0.10 m
The formula for the electrostatic force is given by;
[tex]\rm F=\frac{ Kq_1q_2}{r^2} \\\\ \rm F=\frac{ 9\times 10^9 \times(1.6\times 10^{-19})^2}{(0.1)^2}\\\\ \rm F =2.30 \times 10^{-26} \ N[/tex]
Hence the magnitude of the electrostatic force will be 2.30×10⁻²⁶N.
To learn more about the electrostatic force refer to the link;
https://brainly.com/question/9774180
