Answer:
45 km/h
50 km/h
Step-by-step explanation:
Distance traveled in one way = 450 km
Let x = Velocity when he was going to his destination in km/h
He traveled 5 km/h faster when he returned so his velocity was [tex]x+5[/tex]
It took him 1 hour less when he returned so
[tex]\dfrac{450}{x}-\dfrac{450}{x+5}=1\\\Rightarrow x^2+5x-2250=0\\\Rightarrow x=\frac{-5\pm \sqrt{5^2-4\times 1\times \left(-2250\right)}}{2\times 1}\\\Rightarrow x=45,-50[/tex]
So, velocity while going to his destination is 45 km/h
While returning his velocity was 45+5 = 50 km/h.
