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The last time I posted this question some random person took the points so DONT DO IT AGAIN (YOU KNOW WHO YOU ARE)Write the equation of a line in slope-intercept form with a slope of 10 and passes through (–4, – 25).

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xKelvin

Answer:

[tex]y=10x+15[/tex]

Step-by-step explanation:

We want the equation of a line with a slope of 10 and passes through (-4, -25).

We can use the point-slope form given by:

[tex]y-y_1=m(x-x_1)[/tex]

Where m is the slope and (x₁, y₁) is a point.

So, we will substitute 10 for m and (-4, -25) for (x₁, y₁):

[tex]\displaystyle y-(-25)=10(x-(-4))[/tex]

Simplify:

[tex]y+25=10(x+4)[/tex]

Distribute:

[tex]y+25=10x+40[/tex]

Subtract 25 from both sides:

[tex]y=10x+15[/tex]

And we have our equation.

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