HELP PLEASE. The areas of the squares adjacent to two sides of a right angle are shown above. what is the area of the Square adjacent to the third side of the triangle?

Answer:
6.5units
Step-by-step explanation:
Find the length side of the smaller square
The area of the square is equal to
A = a^2
so
a^2 = 13
a = √13 units
step 2
Find the length side of the larger square
The area of the square is equal to
A = b^2
so
b^2 = 29.25
b = √29.25 units
step 3
Find the value of x
Applying the Pythagoras Theorem
x^2 = a^2 + b^2
x^2 = 13 + 29.25
x^2 = 42.25 units
x = √42.25
x = 6.5 units
The area of the square adjacent to the third side of the triangle is 85 square units.
Important information:
According to the Pythagoras theorem:
[tex]a^2=b^2+c^2[/tex]
Where, a is hypotenuse and b, c are two legs of a right-angle triangle.
Area of a square is the square of side length. So, [tex]b^2=35[/tex] and [tex]c^2=50[/tex]. Now,
[tex]a^2=35+50[/tex]
[tex]a^2=85[/tex]
Therefore, the area of the square adjacent to the third side of the triangle is 85 square units.
Find out more about 'Pythagoras theorem' here:
https://brainly.com/question/22732387