At $350 per person, an airline anticipates selling 200 tickets for a particular flight. At $450 per person the airline anticipates selling 100 tickets for the same flight .

At $350 per person, an airline anticipates selling 200 tickets for a particular flight. At $450 per person the airline anticipates selling 100 tickets for the same flight .Find the linear equation between the cost per ticket and the number of tickets.

Find the complete question attached

Let x be the total number of tickets sold

C be the cost per ticket

If C = $350, x = 200

when C = $450, x = 100

Get the slope

m = C2-C1/x2-x1

m = 450-350/100-200

m = 100/-100

m = -1

Substituting into the point slope form of the equation;

C - C1 = m(x-x1)

Substituting m = -1, C1 = 350 and x1 = 200

C - 350 = -1(x-200)

C - 350 = -x + 200

C = -x + 200 + 350

C = -x + 550

Hence the required linear equation is C =-x + 550

andromache andromache · Answer 2 · 2022-02-22T11:20:15+01:00

The linear equation should be C =-x + 550

Linear equation:

Here we assume x be the total number of tickets sold

And,

C be the cost per ticket

Since C = $350, x = 200 and C = $450, x = 100

So, here the slope should be

[tex]m = C2-C1\div x2-x1\\\\m = 450-350\div 100-200\\\\m = 100\div -100[/tex]

m = -1

Now here we Substituting into the point slope form

So,

C - C1 = m(x-x1)

Here m = -1, C1 = 350 and x1 = 200

Now

C - 350 = -1(x-200)

C - 350 = -x + 200

C = -x + 200 + 350

C = -x + 550

It is an incomplete question. Please find the complete question below.

At $350 per person, an airline anticipates selling 200 tickets for a particular flight. At $450 per person the airline anticipates selling 100 tickets for the same flight .Find the linear equation between the cost per ticket and the number of tickets.

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