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Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of gold from 22 °C to 85 °C?

Respuesta :

Sarah06109

Answer:

[tex]\boxed {\boxed {\sf 121.905 \ J }}[/tex]

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

[tex]q= mc \Delta T[/tex]

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

[tex]m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C[/tex]

Substitue the values into the formula.

[tex]q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)[/tex]

Multiply the first numbers together. The grams will cancel.

[tex]q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)[/tex]

Multiply again, this time the degrees Celsius cancels.

[tex]q= 121.905 \ J[/tex]

121.905 Joules are required.

Answer:Approximately

146.54 joules.

Explanation:

The specific heat equation, which states that:

q=mcΔT

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