Respuesta :
Answer:
L = 1.61 cm
Explanation:
The frequency of open organ pipe is given by :
[tex]f=\dfrac{nv}{2L}[/tex]
Where
n = 1 for fundamental frequency
f = 10500 Hz
L is the length of the pipe
v is the speed of sound, v = 340 m/s
So,
[tex]L=\dfrac{nv}{2f}\\\\L=\dfrac{1\times 340}{2\times 10500 }\\\\L=0.0161\ m\\\\or\\\\L=1.61\ cm[/tex]
So, the length of the pipe is 1.61 cm.
