Answer:
Energy transferred, Q = 20790 J
Explanation:
Given that,
The change in temperature of the liquid, [tex]\Delta T = 15^{\circ} C[/tex]
The mass of liquid, m = 0.33 kg
The specific heat capacity of the liquid is 4200 J/kg°C.
We need to find the energy transferred from the liquid as it cools. The energy transferred is given by :
[tex]Q=mc\Delta T\\\\Q=0.33\times 4200 \times 15\\\\Q=20790\ J[/tex]
So, 20790 J of energy is transferred from the liquid as it cools.
