Suppose there is a 3Mbps uplink and 10Mbps downlink between a geostationary satellite and the base station on earth. If the propagation speed is the speed of light (3 * 10^8 m/sec), the packet size is 20Mb, and the distance from the satellite to earth is 36,000 km, what is the uplink propagation delay of the link in milliseconds

Respuesta :

Answer:

[tex]120\ \text{ms}[/tex]

Explanation:

Distance between the satellite and Earth = [tex]36000\ \text{km}[/tex]

Speed of light = [tex]3\times 10^8\ \text{m/s}[/tex]

Propagation delay is given by distance by the speed of light

[tex]\dfrac{36000\times 10^3}{3\times 10^8}[/tex]

[tex]=0.12\ \text{s}\times 10^3[/tex]

[tex]=120\ \text{ms}[/tex]

The uplink propagation delay of the link is [tex]120\ \text{ms}[/tex].

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