The percentage of fluorine in the given compound is 49%.
The given compound;
CaF₂
The molecular mass of the given compound is calculated as follows;
CaF₂ = (40) + (19 x 2)
= 40 + 38
= 78 g/mol
The mass of fluorine in the given compound = 38 g/mol
The percentage of fluorine in the given compound is calculated as follows;
[tex]= \frac{38}{78} \times 100\%\\\\= 48.7 \%\\\\\approx 49\%[/tex]
Thus, the percentage of fluorine in the given compound is 49%.
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