The rate of distance which is the average speed driven by Larry is; (d1 + d2)/(t1 + t2) = 50 mph
We are given;
First distance driven by Larry = 225 miles
First time by Larry = 4.5 hours
Second Distance driven by Larry = 375 miles
Second time by Larry = 7.5 hours
Formula for rate of distance which is speed is;
s = d/t
where;
d is distance
t is time
Thus;
Rate = (225 + 375)/(4.5 + 7.5)
Rate = 600/12
Rate = 50 mph
Read more about mathematical rates at; https://brainly.com/question/8728504
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