Answer:
Explanation:
In this case, we can do this by thinking a little.
Both ways use a grignard reagent, the difference between both ways is that one use an electrophile ketone with a low molecular mass, and the other has a high molecular mass.
The grignard reagent is commonly used to reduce carbonyle groups to alcohols. In the first step, a complex with the reagent is formed in the carbonile, and in the second step, the oxygen atom is hidrated in acid or basic medium and form the respective alcohol.
For the first way, we will use a high molecular mass ketone. In this case the 2-pentanone reacting with CH₃MgBr as a grignard reagent.
For the second way, we will use a low molecular mass ketone, in this case Acetone, reacting with CH₃CH₂CH₂MgBr. Both of them, will give the same product of 2 methyl-2-pentanol. See picture below for that
Hope this helps
