Answer:
$84
Explanation:
The coefficient of performance (COP) show the relationship between the power (kW) output of the heat pump and the power (kW) input to the compressor.
The heater consumed by the heater is 1200 kWh.
For a heat pump with a COP of 2.4, the electric input needed to produce an output of 1200 kWh is:
Electric input to heat pump = 1200 / 2.4 = 500 kWh
That means that supplying a heat pump with 500 kWh produces an output of 1200 kWh
The amount of power saved = power consumed by heater - power consumed by heat pump = 1200 - 500 = 700 kWh
Money saved = $0.12/kWh * 700 kWh = $84
The amount of money the homeowner would have saved during the month is $84.
Given the following data:
To determine the amount of money the homeowner would have saved during the month:
In Science, the coefficient of performance (COP) is a mathematical expression that is typically used to show the relationship between the power output (kilowatts) of a heater and the power input (kilowatts) to the compressor.
Mathematically, the coefficient of performance (COP) is given by the formula:
[tex]COP = \frac{E_o}{E_i}[/tex]
Where:
First of all, we would determine the energy input of the heaters.
[tex]E_i = \frac{E_o}{COP} \\\\E_i=\frac{1200}{2.4}[/tex]
Energy input = 500 kWh
For power saved:
[tex]Power = 1200 -500[/tex]
Power = 700 kWh
For the amount of money saved while using these heaters:
[tex]Money = 0.12 \times 700[/tex]
Amount of money = $84
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