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In ideal gas equation calculations, expressing pressure in Pascals (Pa), necessitates the use of the gas constant, R, equal to ________. In ideal gas equation calculations, expressing pressure in Pascals (Pa), necessitates the use of the gas constant, R, equal to ________. 8.314 m3-Pa/mol-K 0.08206 atm L mol-1K-1 1.987 cal mol-1K-1 62.36 L torr mol-1K-1 none of the above

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Answer:

[tex]8.314\ \text{m}^3\text{Pa/mol K}[/tex]

Explanation:

Let us find the unit of the gas constant R from the ideal gas equation. We substitute the units of the quantities rearrange them and get the units of the gas constant.

P = Pressure = Pa

V = Volume = [tex]\text{m}^3[/tex]

n = Moles = mol

T = Temperature = K

[tex]PV=nRT\\\Rightarrow R=\dfrac{PV}{nT}\\\Rightarrow R=\dfrac{\text{Pa m}^3}{\text{mol K}}[/tex]

Here, [tex]\text{Pa}[/tex] is used so the gas constant value that must be used is [tex]8.314\ \text{m}^3\text{Pa/mol K}[/tex].

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