Answer:
Final dilution is [tex]\frac{1}{6.33}[/tex]
Explanation:
Given
Volume of suspension [tex]= 3[/tex] mL
Volume of subculture [tex]= 1.5[/tex] mL
Volume of fresh media [tex]= 8[/tex] mL
Final dilution
[tex]\frac{1.5}{8+1.5}[/tex]
Final dilution
[tex]= \frac{1.5}{9.5}\\\\= \frac{15}{95} \\= \frac{1}{6.33}[/tex]