Answer:
[tex] V_{p} = 15 V [/tex]
Explanation:
Given the following data;
Number of loops in primary coil, Np = 1 loop.
Number of loops in secondary coil, Ns = 8 loops
Voltage in secondary coil, Vs = 120V
To find the voltage in the primary coil, Vp;
Transformer ratio is given by the formula;
[tex] \frac{V_{p}}{V_{s}} = \frac{N_{p}}{N_{s}}[/tex]
Making Vp the subject of formula;
[tex] V_{p} = \frac{N_{p}}{N_{s}} * V_{s} [/tex]
Substituting into the equation, we have;
[tex] V_{p} = \frac{1}{8} * 120 [/tex]
[tex] V_{p} = \frac{120}{8} [/tex]
[tex] V_{p} = 15 V [/tex]
Therefore, the voltage in the primary coil, Vp is 15 Volts.
