Answer:
Option A
Step-by-step explanation:
Good question!
We assume that x lies on the interval 0<=x<=360. We can therefore identify the solution in degrees:
[tex]\cos \left(x\right)-\sqrt{1-3\cos ^2\left(x\right)}=0,\:0\le \:x\le \:360^{\circ \:}[/tex]
Now we can solve by substitution, and when simplified we get cos(x) = 1/2.
Take the inverse: x = cos^-1(1/2) = π/3 <--- angle in first quadrant
x = (2π-π/3) = 5π/3 <----- angle in fourth quadrant
As you know π/3 in degrees is 60, and 5π/3 = 360-60 = 300
Therefore your solution is the first option, x = 60+n360 and x = 300 + n360
