Find five solutions for the linear equation 2/4 X + Y =22. Help!!
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Answer:
x the link is https://socratic.org/questions/how-do-you-solve-the- system-of-linear-equations-5x-4y-7-2y-6x-22
=
3
and
y
=
2
.
Explanation:
5
x
−
4
y
=
7
2
y
+
6
x
=
22
From the second equation, we can determine a value for
4
y
.
2
y
+
6
x
=
22
Multiply all terms by
2
.
4
y
+
12
x
=
44
Subtract
12
x
from both sides.
4
y
=
44
−
12
x
In the first equation, replace
4
y
with
(
44
−
12
x
)
.
5
x
−
4
y
=
7
5
x
−
(
44
−
12
x
)
=
7
Open the brackets and simplify. The product of two negatives i a positive.
5
x
−
44
+
12
x
=
7
17
x
−
44
=
7
Add
44
to both sides.
17
x
=
51
Divide both sides by
17
.
x
=
3
In the second equation, substitute
x
with
3
.
2
y
+
6
x
=
22
2
y
+
(
6
×
3
)
=
22
2
y
+
18
=
22
Subtract
18
from both sides.
2
y
=
4
Divide both sides by
2
.
y
=
2
x
=
3
and
y
=
2
.
Explanation:
5
x
−
4
y
=
7
2
y
+
6
x
=
22
From the second equation, we can determine a value for
4
y
.
2
y
+
6
x
=
22
Multiply all terms by
2
.
4
y
+
12
x
=
44
Subtract
12
x
from both sides.
4
y
=
44
−
12
x
In the first equation, replace
4
y
with
(
44
−
12
x
)
.
5
x
−
4
y
=
7
5
x
−
(
44
−
12
x
)
=
7
Open the brackets and simplify. The product of two negatives i a positive.
5
x
−
44
+
12
x
=
7
17
x
−
44
=
7
Add
44
to both sides.
17
x
=
51
Divide both sides by
17
.
x
=
3
In the second equation, substitute
x
with
3
.
2
y
+
6
x
=
22
2
y
+
(
6
×
3
)
=
22
2
y
+
18
=
22
Subtract
18
from both sides.
2
y
=
4
Divide both sides by
2
.
y
=
2
Step-by-step explanation: