Answer:
Known two points, list function expression, use
[tex]y-y_{0}=k(x-x_{0})[/tex]
[tex]k= \frac{y_{2} -y_{1\\}}{x_{2} -x_{1} }[/tex]
The function expression is
[tex]y=\frac{4}{7}x-3[/tex]
It is known that the cross section of two points is 7, so the point of 2:3 is 14 / 5, that is, 0 + 14 / 5 is the abscissa of the point, which is substituted into the original equation to get y = - 7 / 5.
So the result is [tex](\frac{14}{5} ,-\frac{7}{5} )[/tex]