Respuesta :

Use the formula
(b/2)*2
in order to create a new term. Solve for
by using this term to complete the square.
Cannot solve by completing the square.

Answer:

[tex]x^2-2ax+b=0\\or, x^2-2ax = -b\\or, x^2-2ax+a^2=a^2-b\\or, (x-a)^2 = a^2-b\\or, (x-a) =\sqrt{a^2-b} , -\sqrt{a^2-b} \\or, x =a+\sqrt{a^2-b} ~OR~x=a-\sqrt{a^2-b}[/tex]