Answer:
1. area of new pen = 11 [tex]\frac{1}{4}[/tex] [tex]ft^{2}[/tex]
2. i. 5 feet by 2[tex]\frac{1}{4}[/tex] feet
ii. 2 ½ feet by 4 ½ feet
Step-by-step explanation:
The size of the pen as planned = 5 ft long by 4 ½ ft wide
Area of the pen = length x width
= 5 x 4 ½
= 5 x [tex]\frac{9}{2}[/tex]
Area of the pen = [tex]\frac{45}{2}[/tex]
= 22 ½ [tex]ft^{2}[/tex]
But, Krista has to make the pen ½ the size of planned. So that;
area of new pen = ½ x 22 ½
= ½ x [tex]\frac{45}{2}[/tex]
= [tex]\frac{45}{4}[/tex]
= 11 [tex]\frac{1}{4}[/tex]
area of new pen = 11 [tex]\frac{1}{4}[/tex] [tex]ft^{2}[/tex]
The area of the new pen would be 11 [tex]\frac{1}{4}[/tex] [tex]ft^{2}[/tex].
The possible values she could use are:
i. 5 feet by 2[tex]\frac{1}{4}[/tex] feet
ii. 2 ½ feet by 4 ½ feet
