Respuesta :
Answer:
Step-by-step explanation:
The quadratic equation [tex]y = -6x^2 + 100x - 180[/tex] models the store’s daily profit, y, for selling soccer balls at x dollars.
The quadratic equation [tex]y = -4x^2 + 80x - 150[/tex] models the store’s daily profit, y, for selling footballs at x dollars.
Now we are supposed to find the intersection point(s) of the graphs using graphing calculator
Refer the attached graph.
[tex]y = -6x^2 + 100x - 180[/tex] -- Green line
[tex]y = -4x^2 + 80x - 150[/tex] -- Purple line
So, from the graph we can see there are two intersection points :
(8.333,236.667)
(2.053,0)
So, from solution (8.333,236.667) we depict that at x = 8.333 dollars the store's daily profit y = 236.667 for selling football or soccer ball.
From solution (2.053,0)we depict that at x = 0 dollars the store's daily profit y = 2.053 for selling football or soccer ball.
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Answer:
see explanation
Step-by-step explanation:
The quadratic equation models the store’s daily profit, y, for selling soccer balls at x dollars.The quadratic equation models the store’s daily profit, y, for selling footballs at x dollars.Now we are supposed to find the intersection point(s) of the graphs using graphing calculatorRefer the attached graph. -- Green line -- Purple line So, from the graph we can see there are two intersection points :(8.333,236.667)(2.053,0)So, from solution (8.333,236.667) we depict that at x = 8.333 dollars the store's daily profit y = 236.667 for selling football or soccer ball.From solution (2.053,0)we depict that at x = 0 dollars the store's daily profit y = 2.053 for selling football or soccer ball.