the wavelength equation is
speed (of light in this case)= wavelength (m) x frequency
3x10^8m/s / .07m = f
frequency= 4 285 714 286 hertz
b) Total distance= 4.8 km (4,800 m)
Speed = 3x10^8 m/s
d=st
t= d/s
t= 4,800 m/3x10^8m/s
t= 1x10^-5 seconds
Answer:
a) frequency = [tex]7.5 \times 10^9 hz[/tex]
b) times = [tex]3.2 \times 10^{-5} s[/tex]
Explanation:
Part a)
As we know that frequency of radiation is given as
[tex]frequency = \frac{speed}{wavelength}[/tex]
now we know that
[tex]speed = 3 \times 10^8 m/s[/tex]
[tex]wavelength = 4 cm[/tex]
now frequency is given as
[tex]f = \frac{3 \times 10^8}{4 \times 10^{-2}}[/tex]
[tex]f = 7.5 \times 10^9 Hz[/tex]
Part b)
Time required for the pulse to reach the airplane and return is given by formula
[tex]t = \frac{distance}{speed}[/tex]
total distance for moving to and fro = 4.8 km + 4.8 km = 9.6 km
speed of the wave = [tex]3 \times 10^8 m/s[/tex]
now times is given as
[tex]t = \frac{9.6 \times 10^3}{3 \times 10^8}[/tex]
[tex]t = 3.2 \times 10^{-5} s[/tex]
