Respuesta :
E = hxf, où h = constante de Planck = 6,626 x 10 ^ -34Js
E = 6,626 x 10 ^ -34 x 8.11 x 10 ^ 14 = 5.373 10^ -19 J
Hope this answers your question, Kimmyers14!
E = 6,626 x 10 ^ -34 x 8.11 x 10 ^ 14 = 5.373 10^ -19 J
Hope this answers your question, Kimmyers14!
Answer:
Energy, [tex]E=5.37\times 10^{-19}\ J[/tex]
Explanation:
The frequency of the electromagnetic radiation, [tex]f=8.11\times 10^{14}\ hz[/tex]
We need to find the energy of one quantum of this radiation. The energy and frequency follows the following relationship as :
[tex]E=h\times f[/tex]
[tex]E=6.63\times 10^{-34}\times 8.11\times 10^{14}[/tex]
[tex]E=5.37\times 10^{-19}\ J[/tex]
So, the energy of one quantum of this radiation [tex]5.37\times 10^{-19}\ J[/tex]. Hence, this is the required solution.