in Youngstown, the population reached 4420 people in 1993. in 1998 the population was 5600 residents. what was the population in the year 2000?

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10-11-2016
Mathematics

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in Youngstown, the population reached 4420 people in 1993. in 1998 the population was 5600 residents. what was the population in the year 2000?

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texaschic101 texaschic101 · Answer 1 · 2016-11-10T15:36:55+01:00

texaschic101 texaschic101

10-11-2016

5600 - 4420 = 1180....so there is a difference of 1180 in a period of (1998 - 1993) = 5 yrs.

1180/5 = 236 people per yr

so in 1998 the population was 5600.....in 2000 (2 yrs later) the population would be : 5600 + 236(2) = 5600 + 472 = 6072 <==

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