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An owl is carrying a mouse to the chicks in its nest. It is 4.00 m west and 12.0 m above the center of the 30 cm diameter nest and is flying east at 4.50 m/s at an angle 35Á below the horizontal when it accidentally drops the mouse. Will it fall into the nest? Find out by solving for the horizontal position of the mouse (measured from the point of release) when it has fallen the 12.0 m.

Respuesta :

pkmnmushy
Actually it doesn't fall into the nest
Vertical component of the velocity, v of mouse after travelling vertical distance of 12 m is given by 
v^2 - (4*sin 35)^2 = 2*9.81*12 or v = 15.51 m/s 
time taken to travel 12 m downwards = (15.51 - 4*sin 35)/9.81 = 1.35 s 
Horizontal distance traveled in this time = 4*(cos 35)*1.35 = 4.41 m 
But the eastern end of the nest is only 4.15 m away

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