Answer:
Option A [tex]-4[/tex] and [tex]0[/tex]
Step-by-step explanation:
we have
[tex]x^{2}+y^{2} =16[/tex] -----> equation A
This is the equation of a circle with center at the origin and radius [tex]4[/tex] units
[tex]y=x+4[/tex] -----> equation B
This is the equation of a line
we know that
The solution of the system of equations is the intersection point both graphs
using a graphing tool
The intersection points are [tex](-4,0)[/tex] and [tex](0,4)[/tex]
see the attached figure
therefore
the x-coordinates of the solution are [tex]-4[/tex] and [tex]0[/tex]
