Answer:
Step-by-step explanation:
Given is a binomial as
m+2 and we have to raise to power 4.
We know that
[tex](x+a)^n = x^n+nC1 x^{n-1} a+nC2 x^{n-2} a^2+...nCr x^{n-r} a^r+...+a^n[/tex]
Here substitute n =4, x=m and a =2
We get
[tex](m+2)^4 =m^4+4C2 m^3(2) +4C2 m^2 (2^2)+4C3 m (2)^3 +4C4 (2)^4\\= m^4+8m^3+24m^2+32m+16[/tex]
