How many moles of acetic acid and of sodium acetate are present in 50.0 mL of solution?
We calculate it as follows:
moles of acetic acid = .120 mol/L (.050 L ) = 0.006 mol
moles of sodium acetate = 0.150 mol/L (0.050 L) = 0.008 mol
Hope this answers the question. Have a nice day.
