Answer:
6[tex]t^{2}[/tex]-18 is the first one, the second one is 12[tex]t^{2}[/tex]-24t
Step-by-step explanation:
The first one is
2t(3t−9)
=(2t)(3t+−9)
=(2t)(3t)+(2t)(−9)
=6[tex]t^{2}[/tex]−18t
Second one is
(−3t)(−4t+8)
=(−3t)(−4t+8)
=(−3t)(−4t)+(−3t)(8)
=12[tex]t^{2}[/tex]−24t
