Gabriel invested $77,000 in an account paying an interest rate of 3%
compounded monthly. Isabella invested $77,000 in an account paying an
interest rate of 4 % compounded quarterly. After 6 years, how much more
money would Isabella have in her account than Gabriel, to the nearest dollar?

Respuesta :

Answer:

Isabella earn [tex]5604.54[/tex] more money than  Gabriel

Step-by-step explanation:

As we know

Compound interest (CI) [tex]= P (1 + \frac{r}{n})^{nt}[/tex]

P is the principal amount

t is the time period

n is the number of time periods

r is the rate of interest

a)  CI for  Gabriel

[tex]= 77000 (1 + \frac{3}{100*12})^{12*6}[/tex] [tex]= 92165.03[/tex] dollars

b) CI for Isabella

[tex]= 77000 (1 + \frac{4}{100*4})^{4*6}[/tex] [tex]= 97769.57[/tex] dollars

Isabella earn [tex]5604.54[/tex] more money than  Gabriel