Answer:
[tex]\rho= 13.3g/L[/tex]
Explanation:
Hello there!
In this case, since are given an ideal gas problem according to the ideal gas law:
[tex]PV=nRT[/tex]
We need to make the following manipulation to get the density:
[tex]PV=\frac{m}{MM} RT\\\\\frac{m}{V}=\rho= \frac{P*MM}{RT}[/tex]
Thus, since the pressure in atm is 1.04 atm, temperature in kelvins is 336 K and the molar mass is 352.02 g/mol; the density turns out to be:
[tex]\rho= \frac{1.04atm*352.02g/mol}{0.08206\frac{atm*L}{mol*K}*336K}\\\\\rho= 13.3g/L[/tex]
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