Weirdarella03
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1. A wave travels at 1,500 m/s with a frequency of 5 hertz. What is its wavelength?
a. 7,500 m
b. 1,505 m
c. 300 m
d. 1,495 m
2. Humans can hear thunder at different frequencies. These correspond to wavelengths ranging from 2.75 to 16.5 meters. If the speed of sound is approximately 330 m/s, what frequencies of thunder can humans hear?
a. 2.75 to 16.5 hertz
b. 907.5 to 5,445 hertz
c. 20 to 120 hertz
d. 0.0083 to 0.05 hertz
3. Two similar waves X and Y travel through the same medium. Wave X has a frequency of 200 hertz and a wavelength of 35 meters. Wave Y has a frequency of 700 hertz. What is the wavelength for wave Y?
a. 4,900,000 meters
b. 122.5 meters
c. 0.1 meter
d. 10 meters
4. California sea lions communicate underwater at frequencies ranging from 500 to 4,000 hertz. The speed of sound in sea water is approximately 1,500 m/s. What are the approximate wavelengths of sound with which the California sea lions communicate?
a. 750,000 to 6,000,000 meters
b. 0.375 to 3 meters
c. 2,000 to 5,500 meters
d. 0.33 to 2.66 meters

Respuesta :

temdan2001

With the use of wave speed formula, below are the answers to the questions

1. C

2. C

3. D

4. B

All the question centered on wave speed, wavelength and wave frequency. The relationship between these three quantities is;

wave speed = wavelength x frequency

That is,

V = Fλ

1. The given parameters are;

V = 1,500 m/s

F = 5 Hz

wavelength λ = V/F = 1500/5 = 300 m

2.) Given that the wavelengths ranging from 2.75 to 16.5 meters and the speed of sound is approximately 330 m/s

When wavelength = 2.75 m

F = V/ λ = 330 / 2.75 = 120 Hz

When wavelength = 16.5 m

F = V/ λ = 330 / 16.5 = 20 Hz

Therefore, the frequencies of thunder humans hear ranges from 20 Hz to 120 Hz

3.) Since the two waves are similar, they will be travelling at the same speed. That is,

Wave speed of X = Wave speed of Y

For wave X and Y respectively;

F = 200 Hz and 700 Hz

λ = 35 m and λm

Find λ of Y by equating the two wave speed. That is,

Fλ for X = Fλ for Y

200 x 35 = 700 λ

λ = (200 x 35)/ 700

λ = 7000 / 700

λ = 10 m

Therefore, The wavelength for wave Y is 10 m

4.) Given that the sea lions  frequencies are ranging from 500 to 4,000 hertz. And the speed of sound in sea water is approximately 1,500 m/s

By using the same formula,

V = Fλ

Make wavelength the subject of formula

λ = V / F

When F = 500 Hz

λ  = 1500/500 = 3 m

When F = 4000 Hz

λ =  1500/4000 = 0.375 m

Therefore,  the approximate wavelengths of sound with which the California sea lions communicate is of the range 0.375 m to 3 m

Learn more about wave here: https://brainly.com/question/12215474

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