Respuesta :

Space

Answer:

[tex]\displaystyle x = 4\sqrt{3}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality

Trigonometry

  • [Right Triangles Only] SOHCAHTOA
  • [Right Triangles Only] cosθ = adjacent over hypotenuse

Step-by-step explanation:

Step 1: Identify Variables

Angle θ = 30°

Adjacent Leg = x

Hypotenuse = 8

Step 2: Solve for x

  1. Substitute in variables [cosine]:                                                                     [tex]\displaystyle cos(30^\circ) = \frac{x}{8}[/tex]
  2. [Multiplication Property of Equality] Isolate x:                                               [tex]\displaystyle 8cos(30^\circ) = x[/tex]
  3. Rewrite:                                                                                                           [tex]\displaystyle x = 8cos(30^\circ)[/tex]
  4. Evaluate:                                                                                                         [tex]\displaystyle x = 4\sqrt{3}[/tex]
yamunasasidharan0808

Answer:

[tex]4\sqrt{3}[/tex]

Step-by-step explanation:

[tex]cos30[/tex] ° = [tex]\frac{x}{8}[/tex]

cos x = [tex]\frac{adjacent }{hypotenuse }[/tex]

[tex]\frac{\sqrt{3} }{2}[/tex] = [tex]\frac{x}{8}[/tex]

x = [tex]\frac{8\sqrt{3} }{2}[/tex]

x = [tex]4\sqrt{3}[/tex]

I hope it helps.

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