Answer: The partial pressure of oxygen is 187 torr.
Explanation:
According to Raoult's law, the partial pressure of a component at a given temperature is equal to the mole fraction of that component multiplied by the total pressure.
[tex]p_1=x_1p_{total}[/tex]
where, x = mole fraction
[tex]p_{total}[/tex] = total pressure
[tex]x_{oxygen}=\frac{\text {moles of oxygen}}{\text {total moles}}[/tex],
[tex]x_{oxygen}=\frac{3.0}{12.33}=0.243[/tex],
[tex]p_{oxygen}=0.243\times 770torr=187torr[/tex]
Thus the partial pressure of oxygen is 187 torr.
