Answer:
it will take 1,000.42 hours to raise the same amount of water.
Explanation:
mass of the water to be raised, m = 4.2 x 10⁵ kg
power applied in lifting the water, P = 4000 W
height through which the water will be lifted, h = 3.500 km = 3,500 m
The power applied the water is given as follows;
[tex]Power = Force \times Velocity\\\\P = FV\\\\P = ma \ \times \ V\\\\P = ma \ \times \ \frac{d}{t} \\\\P = mg \ \times \ \frac{h}{t} \\\\P = \frac{mgh}{t} \\\\t = \frac{mgh}{P} \\\\t = \frac{4.2\times 10^5 \times 9.8 \times 3,500}{4,000} \\\\t = 3,601,500 \ s = 1000.42 \ hours[/tex]
Therefore, it will take 1,000.42 hours to raise the same amount of water.
