football player A has a mass of 110 kg is running on the field is velocity of 2 m/s football player B has a mass of 120 kg and a stationary what if football player a collage of the football player babe what is the total momentum after the collision

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Lanuel

Complete Question:

Football player A has a mass of 110 kg, and he is running down the field with a velocity of 2 m/s. Football player B has a mass of 120 kg and is stationary. What is the total momentum after the collision?

Answer:

Total momentum = 220 Kgm/s.

Explanation:

Given the following data;

For footballer A

Mass, M1 = 110kg

Velocity, V1 = 2m/s

For footballer B

Mass, M1 = 120kg

Velocity, V1 = 0m/s since he's stationary.

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

[tex] Momentum = mass * velocity [/tex]

a. To find the momentum of A;

[tex] Momentum \; A = 110 * 2 [/tex]

Momentum A = 220 Kgm/s.

b. To find the momentum of B;

[tex] Momentum \; B = 120 * 0 [/tex]

Momentum B = 0 Kgm/s.

c. To find the total momentum of the two persons;

[tex] Total \; momentum = Momentum \; A + Momentum \; B [/tex]

Substituting into the equation, we have;

[tex] Total \; momentum = 220 + 0 [/tex]

Total momentum = 220 Kgm/s.

The total momentum after the collision will be 220 Kgm/s.Momentum is equal to its mass multiplied by its velocity.

What is momentum?

The measurement of mass in motion is called momentum. Momentum is equal to its mass multiplied by its velocity. Mathematically it is given as;

Momentum = Mass x Velocity

The given data in the problem is;

m₁ is the mass of player A= 110 kg

m₂  is the mass of player B= 120 kg

v₁ is the velocity of player A= 2m/s

v₂  is the velocity of player B=0m/s

P is the total momentum=?

The momentum of player A;

[tex]\rm P_A= m_A \times v_A \\\\ \rm P_A= 110 \times 2 \\\\ \rm P_A= 220 \ Kgm/sec[/tex]

The momentum of player B;

[tex]\rm P_B= m_B \times v_B \\\\ \rm P_B= 120 \times 0 \\\\ \rm P_B= 0 \ Kgm/sec[/tex]

The total momentum is given by;

Total momentum = momentum of the player A+ momentum of the player B

[tex]\rm P= P_A+P_B \\\\ \rm P= 220+0 \\\\ \rm P=220 \ m/sec[/tex]

Hence the total momentum after the collision will be 220 Kgm/s

To learn more about the momentum refer to the link;

https://brainly.com/question/4956182