Hello! :) please give an explanation for what is wrong and what should be done to fix this issue.[tex]\frac{\sqrt[3]{64} }{\sqrt{64} } = \sqrt[3]{\frac{64}{64} } =1[/tex]

Respuesta :

Nayefx

Answer:

½

Step-by-step explanation:

to understand this

you need to know about:

  • redical

tips and formulas:

  • [tex] \sqrt[n]{ \frac{y}{x} } < = > \frac{ \sqrt[n]{y} }{ \sqrt[n]{x} } [/tex]

let's solve:

  • it's wrong because it doesn't follow the redical formula. it took one cube root and another square root which is wrong. both should be cube root According to the formula

let's fix the issue

  • since there are a cube root and square root therefore we can't use the formula
  1. [tex] \sf simplify \: roots : \\ \tt = \frac{ \sqrt[3]{64} }{ \sqrt{64} } \\ = \frac{4}{8} \\ = \frac{1}{2} [/tex]