Respuesta :
Answer:
[tex] \tt{he \: has \: } \boxed{ \$1.5} \: left.[/tex]
Step-by-step explanation:
[tex]let \: the \: balance \: be \to \: x : then \to\\ 2(0.89) + 6(0.79) + 2(0.99) + x = 10 \\ 1.78 + 4.74 + 1.98 + x = 10 \\ 8.5 + x = 10 \\ x = 10 - 8.5 \\ \boxed{x = 1.5}[/tex]