Answer:
The force of the air on the skydiver's body is:
[tex]F_{air}=637.7\: N[/tex]
Explanation:
Let's recall that when an object reached terminal velocity, the force of the air acting is equal to the weight of the object, so the net force will be zero, that is why the object falls at a constant speed.
Then we have:
[tex]F_{air}=W=mg[/tex]
where:
m is the mass of the skydiver (65 kg)
g is the gravity acceleration (9.81 m/s²)
Therefore, the force of the air on the skydiver's body is:
[tex]F_{air}=65*9.81=637.7\: N[/tex]
I hope it helps you!
