Answer:
The acceleration of the sled is "0.49 m/s²". A further explanation is given below.
Explanation:
The given values are,
Speed,
V = 4.0 m/s
Coefficient of kinetic friction,
μ = 0.05
As we know,
⇒ [tex]F \mu=\mu mg[/tex]
and,
⇒ [tex]a = \mu g[/tex]
On substituting the given values, we get
⇒ [tex]=0.0 5\times 9.8[/tex]
⇒ [tex]=0.49 \ m/s^2[/tex]