Answer:
b. [tex]\frac{2}{3} \: ft[/tex]
Step-by-step explanation:
[tex] \triangle ABE\sim \triangle CDE[/tex]
(AA postulate)
[tex] \therefore \frac{AB}{CD} =\frac{BE}{DE} [/tex]
[tex] \therefore \frac{2}{h} =\frac{24}{8} [/tex]
[tex] \therefore \frac{2}{h} =3 [/tex]
[tex] \therefore h= \frac{2}{3} \: ft[/tex]
