Answer:
The power will be "250 watt". A further explanation is given below.
Explanation:
The given values are:
Force,
F = 50 N
Displacement,
d = 20 m
Time,
t = 2.0 seconds
Whenever the block is pulled, the angle will be "0" i.e., Cos0° = 1
Now,
The work will be:
= [tex]Force\times displacement\times \Theta[/tex]
On substituting the given values, we get
= [tex]50\times 10\times Cos0^{\circ}[/tex]
= [tex]50\times 10\times 1[/tex]
= [tex]500 \ Newton[/tex]
Now,
The Power will be:
= [tex]\frac{Work \ done}{time}[/tex]
= [tex]\frac{500}{2.0}[/tex]
= [tex]250 \ watt[/tex]
