​A jet fighter is going to land on a battleship. The angle of depression it lands at is 20 degrees. If it is 10,000 ft in the air, how far across the sea will it travel?

Respuesta :

fichoh

Answer:

10641.777 feets

Step-by-step explanation:

To obtain the distance to be traveled across the sea, we use trigonometry :

Cosθ = adjacent / hypotenus

Adjacent = 10000

Hypotenus = d

θ = 20°

Cos 20° = 10000 / d

0.9396926 = 10000 / d

d = 10000 / 0.9396926

d = 10641.777

Ver imagen fichoh

The jet fighter will travel 10641.77 ft far across the sea.

It is given that angle of depression it land at is 20°.

It is required to find how far the sea will travel.

What is the trigonometric ratio?

The trigonometric ratio is defined as the ratio of the pair of a right-angled triangle.

We have an angle of depression = 20°

The height from the sea level = 10,000 ft

From the figure:

[tex]\rm cos20 = \frac{Adjacent}{Hypotenuse}[/tex]

[tex]\rm 0.939 = \frac{10000}{d}[/tex]

d = 10641.77 ft

Thus, the jet fighter will travel 10641.77 ft far across the sea.

Know more about trigonometry here:

brainly.com/question/26719838

Ver imagen maheshpatelvVT